# A particle starts from rest to move along x axis.The acceleration of the particle is a =(t-x) m/s^2 During the motion maximum acceleration of the particle is a0=2m/s^2 Find the velocity in m/s of the particle at t=pi/3 s.

$a=(t-x)m/{s}^{2}\phantom{\rule{0ex}{0ex}}v=at=t(t-x)\phantom{\rule{0ex}{0ex}}Asmaximumaccelerationis2\phantom{\rule{0ex}{0ex}}so2=(t-x)\phantom{\rule{0ex}{0ex}}soatt=\pi /3\phantom{\rule{0ex}{0ex}}v=\frac{\pi}{3}\times 2\phantom{\rule{0ex}{0ex}}=2\pi /3m/s$

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