A particle travels 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec.

Dear student
 

Let us assume initial velocity is u and constant acceleration a.

using ,
 s = ut + 1/2 a t^2


For first 5 second,

10 = 5 u + 1/2 × a × 25..........(1)


for next 3 seconds t = 8s and s = 20m

20 = 8 u + 1/2 × a × 64...........(2)


Solving 1 and 2

a = 1/3 and u = 7/6


Now for next 2 seconds t= 10s  and s'

S' = 10 × 7/6 + 1/2 × (1/3) 100

S'=170/6

Now distance travelled in 2 sec = (170/6) - 20
                                                         = 50/6 => 8.3 m
Regards
 

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