A party of 6 is to be formed from 10 boys and 7 girls so as to include 3 boys and 3 girls. In how many different ways can the party be formed if two particular girls refuse to join the same party ?

Let A and B be the two girls that refuse to go together.Case 1. A is going,B is notNo of ways = C310 ×C36Case 2.B  is going,A is notNo of ways = C310 ×C36Case 3. Both A and B are not going.No of ways =C310 ×C35Total ways = C310 ( C36 + C36 +C35 )

  • -7

10C3*5C3

  • 3

M SORRY.it would be..

10c3*(6c3+6c3+5c3)

  • 4
What are you looking for?