A peacock is sitting on the top of a pillar which is9 m high. From a point27 m away from the bottom of the pillar, a snake is coming to its hole at the base of the pillar. Seeing snake, the peacock pounces on it. If their speeds are equal, at what distance from hole, the snake caught?
Dear Student!
AB is the pillar and C is the position of the hole from the bottom of the pillar.
Here, AB = 9m and BC = 27 m
Let peacock catches the snake at a distance x m from the bottom of the pillar.
∴ BD = x and CD = 27 – x
Given, speed of the peacock and the snake are equal.
∴ Distance covered by peacock = Distance covered by snake
In ΔABD,
AD2 = AB2 + BD2
∴ AD2 = (9)2 + x2
Distance covered by peacock =
Distance covered by snake = (27 – x) m
Squaring on both sides, we get
81 + x2 = (27 – x)2
∴ 81 + x2 = 729 + x2 – 54x
Thus, snake is caught at distance 15 m from the hole.
Cheers!