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a person is listening to a tone of 500 Hz sitting at a distance of 450m from the source of the sound . What is the time interval between successive compressions from the source ?

f=500Hz

distance=450m

T=1/f=1/500=0.002s

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f=500Hz

S=450m

T=1/f=1/500=0.002s

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 Remeber tone is a sound of single frequency.

Tone = 500Hz

Therefore by this statement, we know that the wave can travel 500m in 1 second because a tone is a single frequency.distance or wavelength is given as 450 m 

Therefore Distance / Speed = time

450/500=0.9 sec

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i need expert answer

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find the frictional force required to stop a car of mass 500kg over a distance of 50m ,if the initial speed is 72km/hr. also find its initial KE.find the work done in bringing the car to rest
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See basically, distance is given just to confuse you,Don't get confused Frequency=1/time and therefore, time=1/frequency,So it's 1/500= 0.002 seconds
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9gag
 
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 A person has a hearing range from 20 Hz to 20KHz what are the typical wavelength of sound waves in air corresponding to these two frequencies.take the speed of sound in air is 344m/s.
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this is correct ans.

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0.002s
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frequency=1/time
500Hz=1/time
500Hz × time = 1
time = 1/500
time= 0.002sec


hope this answer helps u     :)
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Just ignore the distance,it is useless.Then you can solve it easily.
 
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speed= wavelength *frequency 
let wavelength be ""x" meter
500= 340 x
​x= 500/340=1.47 meter

 
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0.002s
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Frequency (v)=500Hz Frequency =1/t T=1/frequency =1/500 =0.002 sec Thus time interval between two consecutive compression of the given wave = 0.002 sec
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This will be the right ans... Hope it will help u

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Physical
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Please find this answer

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Please find this answer

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f=500Hz

distance=450m

T=1/f=1/500=0.002s
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Sorry no idea...:(
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2.0seconds
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Please find this answer

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