A photon of wavelength 3310 Aofalls on a photo cathode and an electron of energy 3 x 10-9Jis ejected. If the wavelength of the incident photon is changed to 5000 Ao,the energy of the ejected electron is 9.71 x 10-20 J.Calculate the value of Plank's constant and threshold frequency.

Energy of the incident photon = E = hcλenergy of the emitted electron = Ee = E-hν where ϕ is the work functionwhere ν is the threshold frequency.in first case:3×10-9 = h×3×1083310×10-10-hν--- (1)in second case:9.71×10-20 = h×3×1083310×10-10-hν --- (2)we can get the values of h and ν by solving these two equations.

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