A plane wave of intensity 0.9 W/cm2 illuminates a perfectly absorbing cylinder of radius 5 cm and height 10 cm as shown in figure. The force that light exerts on the cylinder in micro newton is
(A) 0.3 (B) 3.0 (C) 0.6 (D) 0.8 

 

Dear student,

The force that light exerts on the absorbing surfaceF=Area×Intensity of lightspeed of light(here only the surface of the cylindrical surface will absorbes the light)F=2πrh×IcF=2π×5×10×0.93×108=94.2×10-8=0.94×10-6 NF=0.94 μNr=5cmh=10cmI=0.9W/cm2r×h×I=(5×10×0.9)Wand unit of F=unit of 2πrh×Ic=watt/ms-1= Newton

Regards,

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