A planet has twice the mass of earth and of identical size. What will be the height above the surface of the planet where its acceleration due to gravity reduces by 36% of its surface?

Gravity on the surface g = 2GMR2 = 2×9.8 = 19.6 m/s2where M is the mass of the earth and r is the radius of the earth.H is the height where gravity is reduced by 36% of g.g' = g(1-2hR)g' = g-36% of gg' = g-36100gg' = 64100gg(1-2hR) = 64100g1-64100= 2hR36100  = 2hRh =18100RAt height equal to the 18%of R gravity is reduecd by 36% of g.

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