A player moves along the boundary of a square ground of side 50m in 200sec What is the displacement - Science - Motion

Question

A player moves along the boundary of a square ground of side 50m in
200sec What is the displacement of the player at the end of the 11
minutes and 40 seconds from his initial position?

Rohit Babu · Accepted Answer

Dear Student,Side of the square ,a= 50m  , time ,t=11 minutes 40seconds=660+40=700secPerimeter of the square =4×a= 4×50 = 200 m  He completes 1 round in 200 s
  So, speed = 200/200 = 1 m/s  So, distance covered in 700s = 700 × 1 = 7000 m  Number of rounds of the square completed in moving through 700 m is = 700/200 = 3
5  In 3 rounds the displacement is zero
 In 0
5 round the farmer reaches the diagonally opposite end of the square from his starting point
So the distance covered will be,d=a2+a2=502+502=5000=2500×2=502mRegards

A player moves along the boundary of a square ground of side 50m in 200sec. What is the displacement of the player at the end of the 11 minutes and 40 seconds from his initial position?