A point object is placed at a distance of 10cm and its real image is formed at a distance of 20cm from a concave mirror.If the object is moved by 0.1cm towards mirror,the image will shift by about...........

1/u + 1/v = 1/f
Here 1/10 + 1/20 = 3/20 = 1/f
  • f = 20/3
1/v = 1/f – 1/u = (u – f)/uf
  • v = uf/(u-f)
dv/du = [(u – f)*f – uf]/(u-f)2     -quotient rule
           = -f2/(u-f)2
[dv/du]f=20/3,u=10 = 4
Δv = [dv/du]f=20/3,u=10 * Δu
      =4*0.1 = 0.4
  therefore the image will shift by 0.4 cm //
 
  • -2
0.4cm away from the object
  • -9
Solved by vishal

  • -1
Answer given below

  • 23
What are you looking for?