A point P divides the line segment joining the points A(2,-3) and B(-5,6) in a particular ratio. If P lies on the line x+y=0, then find the ratio in which it divides the line segment? Share with your friends Share 3 Lovina Kansal answered this Dear student It is given that P divides the line segment joining A2,-3 and B-5,6 in the ratio k:1.So, coordinates of P are -5k+2k+1,6k-3k+1P-5k+2k+1,6k-3k+1 lies on the line x+y=0So, -5k+2k+1+6k-3k+1=0⇒-5k+2+6k-3=0⇒k-1=0⇒k=1So, required ratio is 1:1 Regards 1 View Full Answer Hera answered this Not really sure about this but I hope it's correct 2 Dhivakar Subbaraj answered this Answers are givenbelow by me -2 Mohammed Rashdan answered this Let the ratio be k:1 {mx2 + nx 1 / m + n , my2 + ny1 / m + n } {-5k +2 / k +1 , 6k - 3 / k + 1 } It is given x + y = 0 -5k + 2/ k+1 + 6k - 3 / k + 1 = 0 k - 1 / k + 1 = 0 k = 1 therefore the ratio is 1:1 1 Dhivakar Subbaraj answered this It is not x+y=0 it is xy=0 0 Dhivakar Subbaraj answered this Who has given my answer wrong 0
