~~A point P is such that the sum of the squares of its distances from the two axes of co-ordinates is equal to the square of its distance from the line x-y=1. Find the equation of the locus of P.

Dear Student,Let the point P be (p,q)Distance of (p,q) from x axis is qDistance of (p,q) from y axis is pDistance of (p,q) from x-y-1 = 0 = p-q-112 + 12 = p-q-12p2+q2=p-q-1222p2+2q2=p2+q2+1-2pq+2q-2pp2+q2+2pq-2q+2p-1=0The above equation gives the equation of the locus of point P. Regards

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