a pole 6 m high casts a shadow 2 root 3 m on the ground then the sun's elevation is :

a-60 degrees

b-45 degrees

c - 30 degrees

d-90 degrees

Question

a pole 6 m high casts a shadow 2 root 3 m on the ground then the
sun's elevation is :
a-60 degrees
b-45 degrees
c - 30 degrees
d-90 degrees

Poonam Mittal · Accepted Answer

Given that height (h) or perpendicular (p) of the pole is 6m and base (b) is $2 \sqrt{3}$

Let the angle of the shadow is θ

then we know

$\frac{p}{b} = \tan (θ)$

$\frac{6}{2 \sqrt{3}} = \tan (θ)$

$\frac{3}{\sqrt{3}} = \tan (θ)$

$\frac{3 \sqrt{3}}{\sqrt{3} \times \sqrt{3}} = \tan (θ)$

$\sqrt{3} = \tan (θ)$

⇒ $θ = 60 °$