A pole 6m high is fixed on the top of a tower The angle of elevation of the top of the pole observed from point P on the ground is 60 and the angle of depression of the point p on the top of tower is 45 find height of tower

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​Tan 60°=QS/PQ
⇒ √3=QS/PQ
 ⇒ QS=PQ/√3.....(i)

tan 45°=QR/PQ
  ⇒ 1=QR/PQ
 ⇒  QR=PQ.....(ii)
 

From (i) and (ii)
QS/√3=QR
(QR+6)=√3 QR
 6=1.732 QR-QR
6=0.732 QR
QR=6/0.732=8.19 m

 
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