A power transmission line feeds power at 2200V with a current of 5A to a step down transformer with its primary winding having 4000 turns. Calculate the number of turns and the current in the secondary in order to get output power at 220V.

400 turns and current is 50A
  • -2

Given, input power (Vp )  = 2200V

Number of turns (n1)  = 3000

Output power (Vs)   = 220 V

vs/vp = n2/n1 

​​​​​​​implies, 220/2200 = n2/4000
n2= 400

∴ Number of turns in the secondary winding, n2 = 400 turns.

  • -1
Ip/Is = vp/vs
so, Ip/5 = 2200/220
ip = 5*10 = 50 A
  • -4
Ns/Np=Vs/Vp
and given to us Np =4000 , V=220 & Vp=2200
therefore
Ns= Np x Vs
 
              Vp
 
Ns= 4000 x  220
                     2200
 =>Ns= 400 turns.
Is=Vs xIp
     Vp
=> Is= 220  x5  = 0.5A
            2200

 
  • -4
Ns = 400 turns Is = 50A Output power = 11000 watt
  • 2
What are you looking for?