A projectile is thrown with a velocity vat an angle a with horizontal When the projectile is at a - Physics - Motion in a plane

Question

A projectile is thrown with a velocity vat an angle a
with horizontal When the projectile is at a height equal to half of
the maximum height, the vertical component of the velocity of
projectile is

v sin a * 3
vsin a / 3
vsin a / root 2

Neha Gupta · Accepted Answer

Initial Vertical component of the velocity u = v sinamaximum height is given by:v2-u2 = -2ghat top most height v = 00  -v sina2 = -2ghh = v sina22gh' =h2h' = v sina24gvertical compoenet of the velocity at this pointv'2 -u2 =-2gh'v' =  v sina2-2gv sina24gv' = v sina2

A projectile is thrown with a velocity vat an angle a with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sin a * 3 vsin a / 3 vsin a / root 2

A projectile is thrown with a velocity vat an angle a with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is

v sin a * 3

vsin a / 3

vsin a / root 2