A quantity of 0.3 g of Cu was deposited from CuSO4 solution by passing 4A through the solution for 3.8 min. Calculate the value of faraday constant ? Share with your friends Share 1 Geetha answered this According to Faraday's I law W=ZIT where Z=equivalent wtfaraday constantEq wt= molecular wt 2 as copper has 2 oxidation state 0.3=63.52F × 4 × 3.8F= 63.52 × 0.3 × 4 × 3.8 × 60 (time = 3.8 min = 3.8 × 60 sec) = 96520 coulombs 3 View Full Answer Kartik Goel answered this using W=ZIT where Z=equivalent wt/faraday constant here eq wt= molecular wt /2 as copper has 2 oxidation state 0.3=(64*3.8*60*4)/2F F=97280 0
