A quantity of 0.3 g of Cu was deposited from CuSO4 solution by passing 4A through the solution for 3.8 min. Calculate the value of faraday constant ?

According to Faraday's I law W=ZIT  where Z=equivalent wtfaraday constantEq wt= molecular wt 2 as copper has 2 oxidation state 0.3=63.52F  × 4 × 3.8F= 63.52 × 0.3  × 4 × 3.8 × 60    (time = 3.8 min = 3.8 × 60 sec)   = 96520 coulombs

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using W=ZIT 
where Z=equivalent wt/faraday constant
here eq wt= molecular wt /2 as copper has 2 oxidation state
0.3=(64*3.8*60*4)/2F
F=97280
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