A radioactive substance has 10^8 nuclei. Its half life is 30s. The no, of nuclei left after 15s is nearly

1-2x10^5

2-3x10^6

3-7x10^7

4-5x10^8

The initial number of nuclei, N0 =108
Half life of the radioactive substance, t1/2 = 30 s
Therefore,
N=N0e-λt=N0e-ln2×tt1/2=N0eln2tt1/2=N02tt1/2N=10821530=108212=1082=7.07×107Therefore, the correct option is option 3.

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