a ray of light passes through an equilateral glass prism such that angle of incidence is equal to the angle of emergence.if the angle of emergence is 3/4 times angle of prism.calculate the refractive index of prism.

hey...u can easily find the answer by applying snell's law...sin i/sin r=n..n=refractive index..

hope this helps you...

  • -9

Ans. A=600 , δm=300
i = e = ¾ A = 450 ,
as A + δ = i + e
60 + δ = 45 + 45
or δ = 300
Refractive index,
m = sin a+δm /2 /sin A/2 = sin 600+300/2 / sin 600/2
= sin 450/sin300 = 1/√2 / ½ = √2 = 1.414

  • 25

Ans. A=600 , δm=300
i = e = ¾ A = 450 ,
as A + δ = i + e
60 + δ = 45 + 45
or δ = 300
Refractive index,
m = sin a+δm /2 /sin A/2 = sin 600+300/2 / sin 600/2
= sin 450/sin300 = 1/√2 / 1/3= √2 = 1.414

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Yess. By using snells law we can easily solve this problem
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1.1444
  • -6
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  • -8
YOU CAN FIND ANSWER BY SNELLS LAW
  • 0
Noooooooo........
  • -5
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  • -4
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  • -1
i+e=A+D i=e=3/4A So, using formula given above 3/4 A+3/4A=A+D 1.5A=A+D 1.5A-A=D Therefore D=A/2 (A= 60 as it is equilateral prism) D= 30 Option D is correct answer
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