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A rectangle 50 m by 30 m has 2 m wide paths joining the middle points of the opposite sides and also a path of the same breadth all round it. The remainder is covered with grass as show in the figure. Find the cost of laying out of court with grass at Rs 25 per sq. m and paving the paths at Rs 2 per sq. m, also find the total cost.

$Areaofgrasscourts=\left(50-2-2-2\right)\times \left(30-2-2-2\right)\phantom{\rule{0ex}{0ex}}=44\times 24=1056{m}^{2}\phantom{\rule{0ex}{0ex}}\mathrm{cos}toflayinggrasscourts=25\times 1056=Rupees26,400\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Areaofpaths=Areaofrec\mathrm{tan}gle-Areaofgrasscourt\phantom{\rule{0ex}{0ex}}=50\times 30-1056\Rightarrow 1500-1056\phantom{\rule{0ex}{0ex}}=444{m}^{2}\phantom{\rule{0ex}{0ex}}Costofpavingpath=2\times 444=888{m}^{2}\phantom{\rule{0ex}{0ex}}Total\mathrm{cos}t=26,400+888=Rupees27,288$

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