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?A rectangular plot of land measures 41 metres in length and 22.5 metres in width. A boundary wall 2 metres high is built all around the plot at a distance of 1.5 m from the plot. Find the inner surface area of the boundary wall.

Solution :


The wall is built 1.5 m from the plot so the length and width of wall will be
41+2(1.5)=44m and
22.5+2(1.5)=25.5m.

Inner area of wall will be,2(l+b)×h=2(44+25.5)×2=278m2
 

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