A rod of mass m and length l is made to stand at an angle of 60 degree with the vertical. Potential energy of the rod in this position is

Dear student
Formula of potential energy is U=mghcmjoining the centre of the rod to the table over which it is placed we get the vertical  height of its centre of masssin60=hcml232=2hcmlhcm=3l4U=mg×3l4Regards

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