A rope is stretched between two boats at rest A sailor in the first boat pulls the rope with - Science - Work and Energy

Question

​​​A rope is stretched between two boats at rest
A sailor in the first boat pulls the rope with a constant force of
100 N First boat with the sailor has a mass of 250 kg whereas the
mass of second boat is double of this mass If the initial distance
between the boats was 30 m, the time taken for two boats to meet
each other is (neglect water resistance between boats and water)

Pintu B. · Accepted Answer

Dear Student ,

The force of 100 N acts on both the boats 
Therefore , 250a1=100 and 500a2=100So, a1=0
4 m/s2 and a2=0
2 m/s2The relative acceleration =a1+a2=0
6 m/s2Using the equation of motion , S=ut+12at2⇒100=12×0
6×t2⇒t=18 3 s
Regards