A sample of dolomite contained 45% of CaCO3 , 40% of MgCO3 and 15%clay. Calculate the mass of sulphuric acid of 30% strength required to react completely with 10g of the sample.

experts please give me the answer as soon as possible. its urgent..please...

Given,

In 10 g sample of dolomite, mass of CaCO3 = 45% of 10 g = 4.5 g

   Mass of MgCO3 = 40 % of 10 g = 4 g

  Mass of clay = 1- (4.5+ 4) = 1.5g

Since clay is a physical impurity, it will not react.

Therefore, 10 g sample contains 4.5 + 4 = 8.5 g dolomite.

 

Reaction between dolomite and sulphuric acid:

CaCO3 + MgCO3 + 2H2SO4 → CaSO4 + MgSO4 +2 H2O + 2CO2

   (Dolomite)

 

Now, 184 g of dolomite reacts with 2 moles = 196 g of H2SO4

8.5 g of dolomite reacts with  of H2SO4

 

Let A g of 30% sulphuric acid is required to react with 10 g sample.

Then,

100 x 9 = 30 x A

A= 900/30

  = 30 g

Therefore, 30 g of 30% sulphuric acid is required to completely react with 10 g of sample.

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