A sample of hydrogen gas occupies a volume of 300 ml at 1.2 bar pressure and 50 C. Calculate its volume at 0.45 bar pressure and 700 C.​

Dear Student,

We know that, PV= nRTSo, n=PVRTn will be constant So, P1V1RT1=P2V2RT2or, P1V1T1=P2V2T2P1= 1.2 bar= 1.2 atmV1=300 ml = 0.3 LT1= 50°C= 50+273=323 KP2=0.45 bar=0.45 atmT2= 700°C= 700+273=973 KSo, V2=P1V1T2T1P2=1.2×0.3×973323×0.45=2.40 L

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