a sample of radioactive material contains 1018 atoms .the half life of the material is 2000 days.calculate 1.the fraction remaining after 5000 days 2. the activity of the sample after 5000 days Share with your friends Share 4 Rajesh K Nimat answered this Dear student Half life time T=0.693/λλ=0.693/2000N=N0e(-λt)N=1018e-(0.693/2000)×5000)N=1018e(-1.7325)N=1.77×1017atoms and activity=λN=0.693/2000×1.77×1017=6×013 atoms/secRegard 0 View Full Answer
