a sample of water gas has a composition by volume of 50 % hydrogen 45 % carbon monoxide and 5 %carbon dioxide. calculate the volume in litres at STP of water gas which on treatment with excess of steam will produce 5 litre hydrogen .the equation for the reaction is co + H2O -> CO2 + H2
Let us use 'x' litre of water gas at STP. So it has 0.5x litre of H2 (∵∵ H2 = 50%)
Now from CO + H2O ⟶⟶ CO2 + H2
to 0.45x excess 0.05x 0.5x
t 0 – (0.05x+0.45x) (0.5x+0.45x) (0.05x+0.45x) (0.5x+0.45x)
So total vol. of H2= 0.95 x H2 = 0.95x
but according to question it is 5 litre.
hence 0.95x = 5
∴x = 5.263litre