A semiconductor has an electron concentration of 8 * 1013 cm-3 and a hole concentration of 5 * 1012 cm-3. The electron mobility is 25000 cm2 V-1 sec-1 and the hole mobility is 100 cm2 V-1 s-1. Then, (a) the semiconductor is n-type (b) the conductivity is 320 m mho (c) Both (a) and (b) (d) None of the above Share with your friends Share 2 Vaibhav Tiwari answered this Dear Student, electron concentration=8×1013 cm-3hole concentration=5×1012 cm-3So as the electron concentration is much more than that of the hole concentration, so the semi conductor is n-type.Conductivity, σ=qnMn+pMpσ=1.6×10-198×1013×25000+5×1012×100σ=1.6×10-1920000×1014+5×1014σ=1.6×10-19×20005×1014σ=0.32008 mho/cm 3 View Full Answer