A semiconductor has the electron concentration 0.45 x 1012 m-3 and hole concentration 5 x 1020m-3.Find its conductivity . given electron mobility ' 0.048m2V-1 s-1. charge on electron '1.6 x 10-19 C

Conductivity of semi conductor:

σ = e n μe+p μhHere,e is charge of electron = 1.6×10-19 Cn is number density of electrons (or) electron concentration = 0.45×1012 m3p is number density of holes (or) holes concentration = 5×1020 m3μe is mobility of electrons = 0.048 m2V-1s-1μh is mobility of holes = ? (Not mentioned in the problem)

Mobility of holes is not mentioned in the problem. So, its not possible to calculate the numerical value of conductivity.
Please substitute its value along with other values mentioned as above to find the conductivity of semi conductor.

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