A series combination of two capacitors of value 0.1 & 1microF is connected with a source of voltage 500V.The potential difference in volts across the capacitor of value 0.1microF will be
equivalent capacitance = 1/11 microF
by using Q = CV
given : CEQUIVALENT = 1/11 microF and voltage = 500 V
Q =500/11 microA
so a total of this much charge will flow through the capacitors.
AGAIN, using Q=CV across capacitors :
500/11 = Vcapacitor / 10 {here, Vcapacitor = voltage across 0.1microF capacitor }
Vcapacitor = 5000/11 microV
by using Q = CV
given : CEQUIVALENT = 1/11 microF and voltage = 500 V
Q =500/11 microA
so a total of this much charge will flow through the capacitors.
AGAIN, using Q=CV across capacitors :
500/11 = Vcapacitor / 10 {here, Vcapacitor = voltage across 0.1microF capacitor }
Vcapacitor = 5000/11 microV