A series LCR circuit containing a resistance of 120 ohm has angular resonance frequency 4x10^3 rad/s. At resonance, the voltage across resistance and inductance are 60v and 40v respectively The values of L and C are respectively Share with your friends Share 10 Pintu B. answered this Dear Student , Here in this case the the given data is as follows : Resistance ,R=120Ω ,angularresonance frequency , ω=4×103 rad/svoltage across resistance VR=60 V amnd the voltage across inductance is ,VL=40V .Now potential difference across R is , VR=IR⇒60=I×120⇒I=12 ANow , potential difference across L is ,VL=IωL⇒L=VLIω=4012×4×103=20mHNow at resonance , ωL=1ωC⇒C=1ω2L=10004×103×20=3·125 μF Regards 25 View Full Answer