A shell of mass 0.02 kg is fired by a gun of mass 10 kg. If the muzzle speed of the shell is 80 m/s, what is the recoil speed of the gun?

Dear Student,

mass of shell, m=0.02 kgmass of gun, M=100 kgmuzzle speed, v=80 m/srecoil velocity, V=?According to law of conservation of momentum,Initial momentum=final momentum0=mv+MVV=-mvMV=-0.02×80100=-0.016 m/snegative sign indicates that the gun moves backward as the bullet moves forward.

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you could use conservation of momentum.M1V1=M2V2

0.02*80=10*velocity
0.16m/s is the recoil of the gun.
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