A shooter is standing on the ground and is looking at a bird up in the sky, which is at a vertical distance of 11 m. The shooter points the gun towards the bird at an angle of elevation of 30° with the horizontal.

If the shooter is holding the gun at a height of 1 m from the ground, then what is the horizontal distance between the bird and the shooter?

 

Given that: BC = 11 m and AP = 1m

So, CQ = BC – AP = 11 – 1 = 10 m

Let horizontal distance between the bird and the shooter = x m

In,

Hence, the horizontal distance between the bird and the shooter is 10 m.

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