a shop keeper bought 10 bananas for 100.2 bananas were rotten. he sold remaining bananas at the rate of Rs.11 per banana. find his gain or loss% 6. a shop keeper purchased 100 ball pens for Rs.250.he sold each pen for Rs.4. find the profit percent.

Answer:

a. Cost of 10 bananas = Rs 100

So cost of 1 banana = Rs. 100/10 = Rs. 10.

Since two bananas were rotten, then the man could sell onle 10 -2 = 8 bananas.

Selling price of 1 banana = Rs. 11.

So the selling price of 8 bananas = Rs 11 x 8 = Rs. 88.

Since the selling price is less than the cost price the man had incurred a loss.

Loss = Cost Price - Selling Price = 100 - 88 = Rs. 12.

Loss% = (CP - SP)/CP x 100 = 12/100 x 100 = 12%

Ans: 12%.

b. Cost Price of 100 ball pens = Rs. 250.

So the cost price of 1 ball pen = 250/100 = Rs. 2.50.

Selling Price of 1 ball pen = Rs. 4.

So the selling Price of 100 ball pens = Rs. 4 x 100 = Rs. 400.

Since the selling price is more than cost price the shop keeper has incurred a profit.

Profit = Selling Price - Cost Price = Rs. 400 - Rs. 250 = Rs. 150.

Profit% = (SP - CP)/CP x 100 = 150/250 x 100 = 15 x 4 = 60%.

Ans: 60%.