A shuttle cock used for playing badminton has the shape of a frustum of a cone mounted on a hemisphere (see figure). The diameters of the ends of the frustum are 5 cm and 2 cm , the height of the entire shuttle cock is 7 cm. Find the external surface area. (Take Pie=22/7) .

Given: r1 = 1 cm, r2 = 2.5 cm, h = 6 cm

 

So, External surface area = C.S.A. of frustum + C.S.A. of hemisphere

= π(r1 + r2) l + r12

= π [ (1 + 2.5) 6.18 + 2 × 12 ] cm2

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