A silver electrode is immersed in a saturated Ag2SO4 (aq) The potential difference between silver and the standard hydrogen - Chemistry - Electrochemistry

Question

A silver electrode is immersed in a saturated Ag2SO4 (aq) The
potential difference between silver and the standard hydrogen
electrode is 0 711 V Determine the Ksp of Ag2SO4 Eo
Ag+/Ag is 0 799 V IIT model paper ans is 0 00001705 pls reply fast

Amit Kumar · Accepted Answer

In this case, the silver forms a cell with standard hydrogen
electrode

pH(s), H2(g)atmH+(aq)(1M)||Ag+(aq)|Ag(s)

Nernst equation for this will be:

Ecell=Eocell - 0
059nlog[H+][Ag+]2×pH2        ∴ 0
711 = 0 799 -0
0592log1[Ag+]2            [SHE; pH2=1 atm, (H+) =1M]⇒   log1[Ag+]2=2
978or we can say that[Ag+] = 3
24 ×10-2

As     Ag2SO4  ⇌ 2 Ag+  +  SO42-and [Ag+] = 3
24×10-2[SO42-] = 3 24×10-22=1
62×10-2∴  ksp = [Ag+][SO42-]=(3
24×10-2)×(1 62×10-2) ksp =1
72 × 10-5

A silver electrode is immersed in a saturated Ag2SO4 (aq). The potential difference between silver and the standard hydrogen electrode is 0.711 V. Determine the Ksp of Ag2SO4. Eo Ag+/Ag is 0.799 V IIT model paper. ans is 0.00001705......pls reply fast.

A silver electrode is immersed in a saturated Ag2SO4 (aq). The potential difference between silver and the standard hydrogen electrode is 0.711 V. Determine the Ksp of Ag2SO4. E_o Ag+/Ag is 0.799 V IIT model paper. ans is 0.00001705......pls reply fast.