A simple pendulum has a time period 5 swhen on the Earth's surface and 10 swhen it is taken to a heighthabove the surface of the Earth. Thenhis equal to
  • A)R

    plzsolve this sir using g'= g ( 1 - 2h/R) and not g' = g R^2/ (R+h)^2
    we should get the same ans but i am not getting the same ans?help

  • R2
  • 3R2

  • 0
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