A simple pendulum has a time period T1 when on the Earth's surface and T2 when taken to a height - Physics - Gravitation

Question

A simple pendulum has a time period T1 when on the Earth's
surface and T2 when taken to a height R above the Earth's surface
where R is the radius of the Earth What is the value of T2/T1?

Jyoti Pant · Accepted Answer

Suppose,Acceleration due to gravity on the surface of
earth=g1Acceleration due to gravity at a height h above the earth's
surface=g2Then,g2=g1(RR+h)2T2=2π(Lg2)T1=2π(Lg1)Therefore,T2T1=2π(Lg2)÷2π(Lg1)=g1g2=R+hR=R+RR(Given
that,h=R)T2T1=21or T2:T1=2:1

A simple pendulum has a time period T1 when on the Earth's surface and T2 when taken to a height R above the Earth's surface where R is the radius of the Earth.What is the value of T2/T1?