A=sin inverse (sin (-600 degree)). Then find A

    A= sin-1sin-600°A = sin-1sin-10π3A = sin-1-sin10π3A = sin-1-sinπ+π3A = sin-1-- sin π3A = sin-1sinπ3A = π3

  • 5
       A=sin-1(sin(-600'))
=>  A=sin-1(-sin(2(360')-120'))
=>  A=sin-1(-(-sin(120')))
=>  A=sin-1(sin(90'+30'))
=>  A=sin-1(cos(30'))
=>  A=sin-1(sin(90'-30'))
=>  A=90'-30'
 => A=60'


 
  • 5
What are you looking for?