# A slit of width 0.6 mm is illuminated by a beam of light consisting of two wavelengths 600 nm and 480 nm. The diffraction pattern is observed on a screen 1.0 m from the slit. Find (i) The distance of the second bright fringe from the central maximum pertaining to light of 600 nm. (ii) The least distance from the central maximum at which bright fringes due to both the wavelengths coincide.

Solution
given, width =a=0.6 mm=0.6*10-3 m
and first wavelength =600 nm
now for diffraction, we know, the distance of second bright fringe from central maximum =   $\frac{5\beta }{2}$

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