a small mass attached to a string rotates on a frictionless table top if the tension in the string is increased by pulling the string causing the radius of the circular motion to decrease by a factor of 2,the kinetic energy of mass will? Share with your friends Share 25 Vikas answered this as we know mvr = constant mvr=mv' .r2v' = 2vtherefore new kinetic energy is K.E'=12m(2v)2K.E= 4×K.Eso kinetic energy will become 4 times. 82 View Full Answer