a sol. containing 1.23g of Ca(NO3)2 in 10 g of water boils at 100.93*C . calculate the degree of ionisation of the nitrate (Kb=0.52)

According to Boling point elevationTb = Kb × m =  Kb × W2M2 W1 × 1000 = 0.52 × 1.23164 × 10 × 1000  = 0.39Tb-Tb0 = 0.39Tb = 0.39 + 100 = 100.39Vant Hoff factor i = observed colligative propertyCalculated colligtive property                                   = 100.93100.39 =1.005Degree of ionisation = i-1n-1                = 1.005 -13 -1   (Ca(NO3)2 has 3 ions)     = 0.0025

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