a solid is in the form of a cone of vertical height h mounted on the top base of a right circular cylinder of height 1/3 h. the circumference of the base of the cone and that of the cylinder are both equal to C. if V be the volume of the solid, prove that C= root[(6 pi V) / h]


Here, C = 2πr.....1V=13πr2h+πr2h3=23πr2hr2=3Vπhr=3VπhC=2×π3Vπh=4π2×3Vπh=6πVh

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