A solution of 66g of acetone and 46g of water has a density 0.926 g/cm ^3 .calculate the molarity of water in the solution. Its urgent !!!!!

Dear Student,

Please find below the solution to the asked query:


Mass of water in 1 cm³ of solution = $\left(\frac{46}{66+46}\right)\times 0.926=0.380 g$

Moles of water in 1 cm³ of solution = 0.380 g / 18 g mol^-1 = 0.0211

So, moles of water in 1 Litre or 1000 cm³ of solution = 21.1 moles

Molarity of water in solution = 21.1 M



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