a solution of MgSO4 is electrolysed for 20 min. with a current of 1.5A. what mass of Mg is deposited at cathode? Share with your friends Share 1 Geetha answered this According to Faraday's I law, W = ZIt WhereW - Mass of magnesium depositedZ - electrochemical equivalence = atomic massnF = 242 × 96500I = 1.5 At = 20 minW = 242 × 96500 × 1.5 × 20 = 0.00373 g -1 View Full Answer