a solution prepared by dissolving 1.25g of oil of winter green in 99gof benzene has its bp of 80.31o C .determne the molar massofthis component.bp of benzene=80.1oC ,kb =2.53

Tb = 80.31 - 80.10 = 0.21oC = 0.21 KGiven mass of solute (WB)= 1.25 gKb = 2.53oC kg mol-1Molar mass of solute (MB)= ?Given mass of solvent (WA)= 99 gMB = Kb×WB×1000Tb×WAMB= 2.53×1.25×10000.21×99 = 152 gmol-1

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