A sound wave of frequency 660Hzincidents normally on a perfectly reflecting object. If the speed of sound on air is 330 m s-1,then what is the shortest distance from the wall at which the wave particles have
  1. the maximum displacement
  2. the minimum displacement

Given frequency  f = 660 Hz,  V = 330m/s.Formula of sound wave velocity    V = f×λTherefore    λ = Vf=330660=0.5 m1.  The distance from the wall where displacement of the wave is maximumis λ/2 =0.5/2=0.25m=25cm. 2.  The distance where displacement of the wave is minimum is      λ = 0.5m=50cm.

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