A source is producing 1500 sound waves in 3 sec. If the distance covered by rarefaction and compression be 68cm. find



c)velocity of sound wave

Number of vibrations in 3 seconds=1500
(i) Number of vibrations in 1 second=1500 / 3=500
So, frequency=500
(ii) Distance covered by a compression and an adjacent rarefaction=Wavelength=68 cm
(iii) Velocity of sound wave=v=frequency x wavelength=500 x 68=34000 cm/sec or 340 m/s

  • 51
What are you looking for?