A sphere of mass 40 kg is attraced by a second sphere of mass 15 kg when their centers are 20 cm apart, with a force of 0.1 milligram weight. Calculate the value of gravitational constant.

Here, m1=40 kg,   m2=15 kg,   r=20 cm=0.2 m

Weight, W=0.1 mg   or force, F=9.8×10-6N

Using the expression, G=F×r2m1×m2

We get,
           G=9.8×10-6×0.2×0.240×15   =0.392×10-6600=6.6×10-11 Nm2/kg2

  • 27

m1= 40 kg

m2= 15 kg

d = 20 cm = 0.2 m

W = 0.1 mg

F = 0.0000098 N

G = (F*d2)/ (m1*m2)

= (0.0000098*0.2) / (40*15)

= (0.00000196) / (600)

= 0.00000000326666.............

= 3.27 * 10-9

  • -17

m1= 40 kg

m2= 15 kg

d = 20 cm = 0.2 m

W = 0.1 mg

F = 0.0000098 N

G = (F*d2)/ (m1*m2)

= (0.0000098*0.2) / (40*15)

= (0.00000196) / (600)

= 0.00000000326666....

= 3.27 * 10-9

  • -19

no this ans is wrong as mass 2 in the question is 80 kg and mass 1 is 40 kg

  • -7
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