# A sphere of mass 40 kg is attraced by a second sphere of mass 15 kg when their centers are 20 cm apart, with a force of 0.1 milligram weight. Calculate the value of gravitational constant.

Here,

Weight,

Using the expression, $G=F×\frac{{r}^{2}}{{m}_{1}×{m}_{2}}$

We get,

• 27

m1= 40 kg

m2= 15 kg

d = 20 cm = 0.2 m

W = 0.1 mg

F = 0.0000098 N

G = (F*d2)/ (m1*m2)

= (0.0000098*0.2) / (40*15)

= (0.00000196) / (600)

= 0.00000000326666.............

= 3.27 * 10-9

• -17

m1= 40 kg

m2= 15 kg

d = 20 cm = 0.2 m

W = 0.1 mg

F = 0.0000098 N

G = (F*d2)/ (m1*m2)

= (0.0000098*0.2) / (40*15)

= (0.00000196) / (600)

= 0.00000000326666....

= 3.27 * 10-9

• -19

no this ans is wrong as mass 2 in the question is 80 kg and mass 1 is 40 kg

• -7
What are you looking for?