A spherical ballon of 21cm diameter is to be filled uo with H2 at NTP from a cylinder containing the gas at 20 atm at 27oC.The cylinder can hold 2.82 litre of wayer. the no. of ballons that can be filled up
Volume of 1 balloon to be filled = 4/3 πr3
= 4/3 * 22/7 * (21/2)3 = 4.851 litre
Let n balloons are filled, then total volume of H2 used in filling balloons = 4.851 * n litre
Cylinder of H2 used in filling balloons will also H2, after n balloons are filled:
Volume of cylinder = 2.82 L
Therefore total volume of H2 at NTP = Volume of n balloons + volume of cylinder
= 4.851*n + 2.82 - 1
The volume of H2 at NTP can be found out using this data:
P1V1/T1 = P2V2/T2 or 1*V/273 = 20*2.82/300
Therefore:
V = 20*2.82*273/300 - 2
Both 1 and 2 should be same:
4.851*n + 2.82 = 20*2.82*273/300
Thus, n = 10